A single-phase resistive load with a rating of 38.4 kW at 240 V draws how many amperes?

A single-phase resistive load with a rating of 38.4 kW at 240 V draws how many amperes?

• A. 140 A
• B. 150 A
• C. 160 A
• D. 170 A

Answer: (C)

For a single-phase, resistive load the current is found with I = P / V, since power factor is effectively 1 for a resistor. Convert the power to watts: 38.4 kW = 38,400 W. Then I = 38,400 W ÷ 240 V = 160 A. So the load draws 160 A at 240 V. The other current options would correspond to different power levels (e.g., 140 A = 33.6 kW, 150 A = 36 kW, 170 A = 40.8 kW), which don’t match the given 38.4 kW.

For a single-phase, resistive load the current is found with I = P / V, since power factor is effectively 1 for a resistor. Convert the power to watts: 38.4 kW = 38,400 W. Then I = 38,400 W ÷ 240 V = 160 A. So the load draws 160 A at 240 V. The other current options would correspond to different power levels (e.g., 140 A = 33.6 kW, 150 A = 36 kW, 170 A = 40.8 kW), which don’t match the given 38.4 kW.